import requests

def upload_to_oss(file_path):
    """
    Uploads a file to OSS using the provided API endpoint.
    URL: https://crmapi.dcjxb.yunzhixue.cn/file/upload
    Method: POST
    Form-data: parameter 'file'
    """
    url = "https://crmapi.dcjxb.yunzhixue.cn/file/upload"
    try:
        with open(file_path, 'rb') as f:
            files = {'file': f}
            response = requests.post(url, files=files)
            response.raise_for_status()
            result = response.json()
            # Assuming the response contains the URL in a specific field
            # We'll need to check the actual response format
            # Typical format: {"code": 200, "data": {"url": "..."}} or similar
            if result.get('code') == 200 or result.get('success'):
                # Extract URL - adjusting based on common API patterns
                data = result.get('data', {})
                if isinstance(data, str):
                    return data
                return data.get('url') or data.get('fileUrl') or result.get('url')
            else:
                print(f"Upload failed: {result}")
                return None
    except Exception as e:
        print(f"Error uploading to OSS: {e}")
        return None
